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[LeetCode]Merge Intervals
阅读量:4150 次
发布时间:2019-05-25

本文共 2022 字,大约阅读时间需要 6 分钟。

struct Interval {	int start;	int end;	Interval() : start(0), end(0) {}	Interval(int s, int e) : start(s), end(e) {}};class Solution {//first sort and then merge, O(nlogn)public:	struct comp	{		bool operator()(const Interval& lhs, const Interval& rhs) const		{			if(lhs.start != rhs.start) return lhs.start < rhs.start;			else return lhs.end < rhs.end;		}	};	vector
merge(vector
&intervals) { // Start typing your C/C++ solution below // DO NOT write int main() function if(intervals.size() == 0) return vector
(); sort(intervals.begin(), intervals.end(), comp()); vector
ans; Interval tmp = intervals[0]; for (int i = 1; i < intervals.size(); ++i) { if(intervals[i].start <= tmp.end) tmp.end = max(tmp.end, intervals[i].end); else { ans.push_back(tmp); tmp = intervals[i]; } } ans.push_back(tmp); return ans; }};

second time

/** * Definition for an interval. * struct Interval { *     int start; *     int end; *     Interval() : start(0), end(0) {} *     Interval(int s, int e) : start(s), end(e) {} * }; */class Solution {public:    struct cmp    {        bool operator()(const Interval& a, const Interval& b)const        {            if(a.start == b.start) return a.end < b.end;            else return a.start < b.start;        }    };        vector
merge(vector
&intervals) { // Start typing your C/C++ solution below // DO NOT write int main() function sort(intervals.begin(), intervals.end(), cmp()); vector
newIntervals; for(int i = 0; i < intervals.size();) { int newEnd = intervals[i].end; int j; for(j = i; j < intervals.size(); ++j) { if(intervals[j].start <= newEnd) newEnd = max(newEnd, intervals[j].end); else break; } newIntervals.push_back(Interval(intervals[i].start, newEnd)); i = j; } return newIntervals; }};

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